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x^2+100-29x^2=0
We add all the numbers together, and all the variables
-28x^2+100=0
a = -28; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-28)·100
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{7}}{2*-28}=\frac{0-40\sqrt{7}}{-56} =-\frac{40\sqrt{7}}{-56} =-\frac{5\sqrt{7}}{-7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{7}}{2*-28}=\frac{0+40\sqrt{7}}{-56} =\frac{40\sqrt{7}}{-56} =\frac{5\sqrt{7}}{-7} $
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